A wire of length L and area of cross-section A is made of a material of Young’s modulus Y. If the wire is stretched by the amount x, the work done is
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a
YAx2/2L
b
YAx2L
c
YAx/2L
d
YAx2/L
answer is A.
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Detailed Solution
Y=FA×Lx When a wire is stretched, work is done against the inter atomic forces. This work is stored in wire in the form of elastic potential energy. So, W=12 stress × strain × volume = 12 (Y.strain) × strain × volume=12Y×xL2×A×L=12YAx2L=YAx22L