Questions
A wire of length L is drawn such that its diameter is reduced to half of its original diameter. If the initial resistance of the wire were its new resistance would be
detailed solution
Correct option is C
For a wire of length l, area A, specific resistance ρ, the resistance is given byR= ρ lA ....1If original diameter of wire be d, then new diameter is d/2Original area of cross-section is πd2/4 and final area of cross-section is πd2/16Since volume remains constant, on pulling the wire we haveπd24 × l = πd216 × l'⇒ l' =164 l = 4 lAlso R'= ρ l'A' ....2∴ R'= ρ. 4 lA/4 = 16 RHence, new resistance 16 × 10=160 ΩTalk to our academic expert!
Similar Questions
In an electrical cable there is a single wire of radius 9 mm of copper. Its resistance is 5Ω . The cable is replaced by 6 different insulated copper wires, the radius of each wire is 3 mm . Now the total resistance of the cable will be
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