A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to the current, the temperature of the wire is raised by ∆T in a time t. A number N of similar cells is now connected in series with a wire of same material and cross-section but of length 2 I- The temperature of the wire is raised by the same amount ∆T in the same time t. The value of N is
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a
4
b
6
c
8
d
9
answer is B.
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Detailed Solution
We know that heat developed=i2 R t. Hence3ER12R1t=m1sdtand NER22R2t=m2sdt∴ N29=m2m1×R2R1or N2=9m2m1R2R1N=3m2m1R2R1=32m1m12R1R1=6
A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to the current, the temperature of the wire is raised by ∆T in a time t. A number N of similar cells is now connected in series with a wire of same material and cross-section but of length 2 I- The temperature of the wire is raised by the same amount ∆T in the same time t. The value of N is