A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to current, the temperature of the wire is raised by ΔT in time t. A number N of similar cells is now connected in series with a wire of the same material and cross-sectionbut of length 2L.The temperature of the wire is raised by the same amount ΔT in the same time t. The value of N is
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a
4
b
6
c
8
d
9
answer is B.
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Detailed Solution
Let R and m be the resistance and mass of the first wire, then the second wire has resistance 2R and mass 2m. Let E = emf of each cell, S = specific heat capacity of the material of the wire. For the first wire, current i1 = 3ER and i12 Rt = mSΔTFor the second wire, i2 = NER and i12 2Rt = 2 mSΔT.Thus, i1 = i2 or N=6.