First slide
Electrical power
Question

A wire of length L and 3 identical cells of negligible internal resistances are connected in series. Due to current, the temperature of the wire is raised by ΔT in time t. A number N of similar cells is now connected in series with a wire of the same material and cross-section
but of length 2L.The temperature of the wire is raised by the same amount ΔT in the same time t. The value of N is

Moderate
Solution

Let R and m be the resistance and mass of the first wire, then the second wire has resistance 2R and mass 2m. Let E = emf of each cell, S = specific heat capacity of the material of the wire. For the first wire, current i1=3ER  and  i12  Rt  =  mSΔT

For the second wire, i2=NER and   i12  2Rt  = 2 mSΔT.

Thus, i1  =  i2  or  N=6.

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