Questions
A wire of length and Mass per uniform length is put under tension of . Two consecutive frequencies it resonates at are and . Then in meters is
detailed solution
Correct option is C
Suppose the wire vibrates at 420Hz in its nth harmonic and at 490Hz in its n+1th harmonic. f=n2lTμ ∴490420=n+1n ⇒n=6 Now, from first equation ∴420=62l5006×10−3 ⇒70=12×l500×1036 ⇒140l=5×1056 ⇒l=288.67140=2.0619Talk to our academic expert!
Similar Questions
A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)
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