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Q.

A wire of length l  and mass per unit length 6.0×10−3 kg/m  is put under tension of 540N  two consecutive frequencies that it resonates at are  420 Hz and 490 Hz , then l  in meters is _____

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answer is 0002.14.

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Detailed Solution

nv2l=420   →   i n+1v2l=490   →  (ii) Divide i/ii            n=6 Substitute in equation (i) we have  ⇒6×v2l=420            Also,  v=Tμ=5406×10−3 ∴6×5406×10−32l=420 l=300140=2.142
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A wire of length l  and mass per unit length 6.0×10−3 kg/m  is put under tension of 540N  two consecutive frequencies that it resonates at are  420 Hz and 490 Hz , then l  in meters is _____