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Q.

A wire of length 'L' and radius 'r' is fixed at one end and a force 'F' is applied to the other end to produce an extension 'l '. The extension produced in another wire of same material of length '3L' and radius '2r' by a force 'F/2' is

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a

3ℓ5

b

5ℓ3

c

3ℓ8

d

8ℓ3

answer is C.

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Detailed Solution

e=FLπr2y e1e2=F1F2×L1L2×(r2r1)2(y2y1) ℓe2=FF/2×ℓ3ℓ(2rr)2(1) ℓe2=2×13×4=83⇒e2=3ℓ8
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