A wire of length L0 is supplied heat to raise its temperature by T. lf γ is the coefficient of volume expansion of the wire and Y is Young's modulus of the wire then the energy density stored in the wire is
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a
12γ2T2Y
b
13γ2T2Y3
c
118γ2T2Y
d
118γ2T2Y
answer is D.
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Detailed Solution
Due to heating the length of the wire increases.∴Longitudinal strain is produced⇒ ΔLL=α×ΔTElastic potential energy per unit volume E=12× Stress × Strain =12×Y×( Strain )2⇒E=12×Y×ΔLL2=12×Y×α2×ΔT2or E=12×Y×γ32×T2=118γ2YT2 [As γ=3α and ΔT=T (given) ]