Q.

A wire length π2m, carrying a current of 2A is bent in the form of a circular are which subtends on angle of 45° at its centre. Then magnetic induction at the centre is

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a

µo / 8 T

b

µo / 16 T

c

µo / 2 T

d

4 µo T

answer is B.

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Detailed Solution

l=R.θ⇒R=π/2π/4m=2m ∴Bo=μoi2R.θ2π=μo×22×2×π/42πT ⇒Bo=μo16T
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A wire length π2m, carrying a current of 2A is bent in the form of a circular are which subtends on angle of 45° at its centre. Then magnetic induction at the centre is