Q.

24. A wire of length 2 m is moving at a speed of 5ms–1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 Ω. The rate at which work is being done to keep the wire moving at constant speed is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

512W

b

52W

c

53W

d

1 W

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Rate of work   =Wt=P=Fv;       also        F=Bil=B BvlR l⇒P=B2v2l2R=(0.5)2×(5)2×(2)210=52W
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
24. A wire of length 2 m is moving at a speed of 5ms–1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 Ω. The rate at which work is being done to keep the wire moving at constant speed is