$$24$$. A wire of length $$2$$ m is moving at a speed of $$5ms$$–$$1$$ perpendicular to its length and a homogeneous magnetic field of $$0.5$$ T. The ends of the wire are joined to a circuit of resistance $$10$$ Ω. The rate at which work is being done to keep the wire moving at constant speed is

Question

$$24$$. A wire of length $$2$$ m is moving at a speed of $$5ms$$–$$1$$ perpendicular to its length and a homogeneous magnetic field of $$0.5$$ T. The ends of the wire are joined to a circuit of resistance $$10$$ Ω. The rate at which work is being done to keep the wire moving at constant speed is

Infinity Learn · Accepted Answer

Rate of work   $$=Wt=P=Fv$$;       also        $$F=Bil=B$$ BvlR l⇒$$P=B2v2l2R=(0.5)2$$×$$(5)2$$×$$(2)210=52W$$

24. A wire of length 2 m is moving at a speed of $5 {ms}^{- 1}$ perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 $Ω$ . The rate at which work is being done to keep the wire moving at constant speed is

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24. A wire of length 2 m is moving at a speed of 5ms–1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 Ω. The rate at which work is being done to keep the wire moving at constant speed is

Unlock the full solution & master the concept.

Ready to Test Your Skills?

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24. A wire of length 2 m is moving at a speed of $5 {ms}^{- 1}$ perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 $Ω$ . The rate at which work is being done to keep the wire moving at constant speed is