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24. A wire of length 2 m is moving at a speed of 5ms1 perpendicular to its length and a homogeneous magnetic field of 0.5 T. The ends of the wire are joined to a circuit of resistance 10 Ω. The rate at which work is being done to keep the wire moving at constant speed is 

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a
512W
b
52W
c
53W
d
1 W

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detailed solution

Correct option is B

Rate of work   =Wt=P=Fv;       also        F=Bil=B BvlR l⇒P=B2v2l2R=(0.5)2×(5)2×(2)210=52W

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