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A wire of length 1m and radius 1 mm is subjected to a load. The extension is 'x' . The wire is melted and then draw into a wire of square cross-section of side 1mm . What is its extension under the same load

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a

π2x

b

πx2

c

πx

d

π/x

answer is A.

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Detailed Solution

Volume = const V1=V2 A1ℓ1=A2ℓ2⇒ℓ1ℓ2=A2A1 e=FℓAY as F&Y → samee αℓA⇒e1e2=ℓ1ℓ2.A2A1=(A2A1)(A2A1) xe2=(A2A1)2=(10−6π×10−6)2 e2=π2x

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