First slide

Elastic Modulie

Question

A wire ‘AB’ is suspended about the end A. Marks C and D on it are 40 cm apart. When a load is suspended from B, then the marks C and D are displaced by 0.3 mm and 0.5 mm respectively. The original length of AD is

Easy

A

60 cm
B

100 cm
C

80 cm
D

200/3 cm

Solution

$\large \frac{{{e_{AC}}}}{{{e_{AD}}}} = \frac{{AC}}{{AD}} \Rightarrow \frac{{0.3}}{{0.5}} = \frac{x}{{40 + x}}$
$\large \Rightarrow 3(40 + x) = 5x$
$\large \Rightarrow 120 + 3x = 5x$
$\large 2x = 120 \Rightarrow x = 60cm$
$\large AD = x + 40 = 100cm$

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