A wire 3 m in length and area of cross section 3×10-7m2 originally at 300C is now kept at a low temperature of -1700C and is stretched by hanging a weight of 20 kg at one end. The change in length of the wire is [Y = 2×1011N/m2 g = 10 m/s2 and α = 1.2×10-5/C 0]
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a
25mm
b
2.8mm
c
7.2mm
d
10mm
answer is B.
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Detailed Solution
Here net change in length is the difference in elongation due to the load and contraction due to coolingElongation=FAlY and contraction is lα∆t20×103×10-732×1011-3×1.2×10-5×200 =10×10-3-7.2×10-3 =2.8mm