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Q.

A wire 3m in length and 1mm in diameter at 300C and is kept at temperature 1700C  and is stretched by hanging a weight of 10kg at one end calculate the change in the length of the wire. Given α=1.2×10−5/0C  Y=2×1011Nm−2 g=10ms−2

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a

2×10−3m

b

7.2×10−3m

c

9.2×10−3m

d

5.2 mm

answer is C.

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Detailed Solution

e1=ℓαΔt=3×(1.2×10−5)(170−30) =7.2×10−3me2=FℓAy=2011×10−3m≈2×10−3mΔl=e2+e1=(2+7.2)×10−3=9.2×10−3m =9.2mm
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