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Questions  

A wire shaped as a semicircle of radius o rotates about an axis OO' with an angular velocity ω in a uniform magnetic field of induction B [Fig. (5)]. The rotation

axis is perpendicular to the field direction. The total resistance of the circuit is equal to fl. Neglect the magnetic field of induced current. The mean amount of thermal power being generated into the loop during a rotation period will be

a
12Rπωa2B22
b
12Rπωa2B2
c
12Rπω2aB2
d
12RπωaB22

detailed solution

Correct option is A

Φ=B⋅A=Bπα22cos⁡ωte=−dΦdt=Bπa22ωsin⁡ωtInduced current i=eR=Bπa22Rωsin⁡ωtAt any moment t, the thermal power generated in the circuitPt=e×i=Bπa2ω221Rsin2⁡ωtMean power (P) = Bπa2ω221R∫0T sin2⁡ωt∫0T dt=12Rπωa2B22

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