In a wire stretched by hanging a weight from its end, the elastic potential energy per unit volume in terms of the longitudinal strain σ and modulus of elasticity Y is
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a
Yσ2/2
b
Yσ/2
c
2Yσ2/2
d
Y2σ/2
answer is A.
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Detailed Solution
Elastic potential energy per unit volume=12× stress × strain =12×[ Young'smodulus × strain ]× strain =12×Y×σ2=Yσ22