A wire is suspended vertically from a rigid support. When loaded with a steel weight in air, the wire extends by 16 cm. When the weight is completely immersed in water, the extension is reduced to 14 cm. The relative density of the material of the weight is
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a
2 g cm-3
b
6g cm-3
c
8 g cm-3
d
16 cm-3
answer is C.
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Detailed Solution
Y = Fla∆l; Y, l and a are constants F ∞ ∆lIn the first case Vρg= 16In the second case, (ρg-V×1×g) ∞ 14Dividing, Vg(ρ-1)Vgρ = 1418 = 78or ρ-1ρ= 78 or 8ρ-7ρ or ρ = 8g cm-3