A wire under tension vibrates with a frequency of 450 per second. What would be the fundamental frequency if the wire were half as long, twice as thick and under one-fourth tension
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a
225cps
b
190 cps
c
247 cps
d
174 cps
answer is A.
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Detailed Solution
n=12lTm Here 450=12lTm or 450=12lTπr2ρ n2=12(l/2)(T/4)π(2r)2ρ Solving, we get n2=225Hz