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A wire of uniform cross-section is bent in the shape shown in figure. The co-ordinate of the centre of mass of each side are shown in (figure). The coordinates of the centre of mass of the system are
 

 

 

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a
(15l14, 6l7)
b
(15l14, l)
c
(l, l2)
d
(l, l)

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detailed solution

Correct option is A

Xcm = m×0+ml+m×2l+m23l23.5 m⇒Xcm = 15 ml4×72m = 15l14     Ycm = m×0+ml+ml+m22l72m⇒Ycm = 3ml7m2 = 6l7

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