With the usual notations, the following equation St=u+12a(2t−1) is
Only numerically correct
Only dimensionally correct
Both numerically and dimensionally correct
Neither numerically nor dimensionally correct
We can derive this equation from equations of motion. So it is numerically correct.
St= Distance travelled in tth second = Distance Time =Lu= Velocity =LT−1 and 12a(2t−1)=LT−1
As dimensions of all terms in the given equation are not same, hence equation is not dimensionally correct.