Q.

With the usual notations, the following equation St=u+12a(2t−1) is

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a

Only numerically correct

b

Only dimensionally correct

c

Both numerically and dimensionally correct

d

Neither numerically nor dimensionally correct

answer is A.

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Detailed Solution

We can derive this equation from equations of motion. So it is numerically correct.St= Distance travelled in tth  second = Distance  Time =Lu= Velocity =LT−1 and 12a(2t−1)=LT−1As dimensions of all terms in the given equation are not same, hence equation is not dimensionally correct.
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