Questions
With the usual notations, the following equation is
a
Only numerically correct
b
Only dimensionally correct
c
Both numerically and dimensionally correct
d
Neither numerically nor dimensionally correct
detailed solution
Correct option is A
We can derive this equation from equations of motion. So it is numerically correct.St= Distance travelled in tth second = Distance Time =Lu= Velocity =LT−1 and 12a(2t−1)=LT−1As dimensions of all terms in the given equation are not same, hence equation is not dimensionally correct.Talk to our academic expert!
Similar Questions
If velocity, time and force were chosen as basic quantities, find the dimensions of mass and energy.
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