With the usual notations, the following equation St=u+12a(2t−1) is
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a
Only numerically correct
b
Only dimensionally correct
c
Both numerically and dimensionally correct
d
Neither numerically nor dimensionally correct
answer is A.
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Detailed Solution
We can derive this equation from equations of motion. So it is numerically correct.St= Distance travelled in tth second = Distance Time =Lu= Velocity =LT−1 and 12a(2t−1)=LT−1As dimensions of all terms in the given equation are not same, hence equation is not dimensionally correct.