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Q.

With what minimum acceleration should the wedge move horizontally for which the block B falls freely Take g = 10m/s2

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a

17.32  m/s2

b

5.77  m/s2

c

5  m/s2

d

10  m/s2

answer is A.

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Detailed Solution

The wedge must move to the right. From the frame of the wedge,N+masinθ−mgcosθ = 0∴ masinθ−mgcosθ = 0⇒ a = gcotθ = 10cot300 = 103m/s2 = 17.32m/s2
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