A wooden block of mass 20 kg rests on a frictionless surface. A 0.5 kg bullet, moving with a velocity of 100 m/s pierces the block and emerges with a velocity of 50 m/s. Then velocity of the block after the impact is
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a
1.25 m/s
b
2.5 m/s
c
1.5 m/s
d
3 m/s
answer is A.
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Detailed Solution
Conserving linear momentum,0.5 x 50 + 20 X V = 0.5 X 100 ⇒V=2520m/s =1.25 m/s