A wooden log of mass $$120kg$$ is floating on still water perpendicular to the shore. A man of mass $$80kg$$ is standing at the centre of mass of the log and he is at a distance of $$30m$$ from the shore. When he walks through a distance of $$10m$$ towards the shore and halts, now his distance from the shore is

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Infinity Learn · Accepted Answer

If $$r1$$, $$r2$$ and rc be the distances of COM of the man, boat and COM of the system, then $$m1r1+m2r2$$ $$=$$ (m1+m2).rc. If Δ$$r1$$ $$=$$ (10-x) and Δ$$r2$$ $$=x$$ Distance of man from the shore $$=$$ $$30$$ $$-$$ (10$$ $$-$$ $$4) $$=$$ $$24m$$

A wooden log of mass 120kg is floating on still water perpendicular to the shore. A man of mass 80kg is standing at the centre of mass of the log and he is at a distance of 30m from the shore. When he walks through a distance of 10m towards the shore and halts, now his distance from the shore is

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