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Q.

A wooden log of mass 120kg is floating on still water perpendicular to the shore. A man of mass 80kg is standing at the centre of mass of the log and he is at a distance of 30m from the shore. When he walks through a distance of 10m towards the shore and halts, now his distance from the shore is

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a

20m

b

24m

c

26m

d

28m

answer is B.

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Detailed Solution

If r1, r2 and rc be the distances of COM of the man, boat and COM of the system, then m1r1+m2r2 = (m1+m2).rc. If Δr1 = (10-x) and Δr2 =x Distance of man from the shore = 30 - (10 - 4) = 24m
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