A wooden object floats in water kept in a beaker. The object is near a side of the beaker see (figure). Let P1 , P2 , P3 be the pressures at the three points A, B and C of the bottom as shown in the figure
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a
P1=P2=P3
b
P1
c
P1>P2>P3
d
P2=P3≠P1
answer is A.
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Detailed Solution
Points A, B and C in the bottom are at same horizontal level hence pressure same at all the three points i.e. P1 = P2 = P3.