A wooden rod of a uniform cross section and of length 120 cm is hinged at the bottom of the tank which is filled with water to a height of 40 cm. In the equilibrium position, the rod makes an angle of 600 with the vertical. The centre of buoyancy is located on the rod at a distance (from the hinge) of
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a
20 cm
b
40 cm
c
60 cm
d
75 cm
answer is B.
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Detailed Solution
OP is the portion of the rod immersed in water.cos60∘=40OP or OP=40cos60∘cm=401/2cm=80cmThe centre of buoyancy is at the centre of the immersed part of the rod. So, the required distance is 40 cm.