Work done to blow a bubble of volume V is W. The work done in blowing a bubble of volume 2 V will be

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(2) 1/3W

(4)1/3W

answer is C.

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Detailed Solution

W1=4πr12T and W2=4πr22T ∴ W2W1=r22r12=r23r131/32 =V2V12/3=(2)2/3=(4)1/3 Now W1=W. Hence W2=(4)1/3W

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