The work done in breaking a drop of liquid of radius R into 64 number of identical drops is [Surface tension of liquid is T]

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24 πR2T

16 πR2T

8 πR2T

12 πR2T

answer is D.

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Detailed Solution

If radius of each smaller drop is r, 64×43πr3=43πR3⇒r=R4∴ W=64×4πr2T−4πR2T=64×4πR216.T−4πR2T=12πR2T

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