First slide

Surface tension

Question

The work done in breaking a drop of liquid of radius R into 64 number of identical drops is
[Surface tension of liquid is T]

Moderate

A

24 $π R^{2} T$
B

16 $π R^{2} T$
C

8 $π R^{2} T$
D

12 $π R^{2} T$

Solution

If radius of each smaller drop is $r, 64 \times \frac{4}{3} π r^{3} = \frac{4}{3} π R^{3} \Rightarrow r = \frac{R}{4}$
$∴ W = 64 \times 4 π r^{2} T - 4 π R^{2} T$
$= 64 \times 4 π \frac{R^{2}}{16} . T - 4 π R^{2} T = 12 π R^{2} T$

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