Q.

The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2m is 2J. The potential difference between the two points will be (in volt)

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a

0.2

b

8

c

0.1

d

0.4

answer is C.

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Detailed Solution

By using W=Q⋅ΔV⇒ΔV=220=0.1volt
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Best Online Course for NEET
Best Online Course for CBSE
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