First slide

Electrostatic potential

Question

The work done in bringing a 20 coulomb charge from point A to point B for distance 0.2 m is 2 J. The potential difference between the two points will be (in volt)

Easy

A

0.2
B

8
C

0.1
D

0.4

Solution

$By using W = Q \cdot ΔV \Rightarrow ΔV = \frac{2}{20} = 0.1 volt$

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