Q.
Work done by an external agent in stretching a spring by 1 cm is 9 J, work done in stretching the same spring by 2 cm is 16 J. Then the work done in stretching the same spring by 3 cm is
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a
24 J
b
25 J
c
32 J
d
50 J
answer is B.
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Detailed Solution
W1=12Kx2⇒x=2W1K and y=2W2KW=12K(x+y)2=12K[2W1K+2W2K]2=(W1+W2)2=(4+9)2J=25J
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