Questions
Work done by an external agent in stretching a spring by 1 cm is 9 J, work done in stretching the same spring by 2 cm is 16 J. Then the work done in stretching the same spring by 3 cm is
detailed solution
Correct option is B
W1=12Kx2⇒x=2W1K and y=2W2KW=12K(x+y)2=12K[2W1K+2W2K]2=(W1+W2)2=(4+9)2J=25JTalk to our academic expert!
Similar Questions
Two similar springs P and Q have spring constants such that Kp > . They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs are related as, in case (a) and case (b), respectively.
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