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Questions  

The work done by external agent in stretching a spring of force constant k from length l1 to l2 is

a
k(l22-l12)
b
12k(l22-l12)
c
k(l2-l1)
d
k2(l2+l1)

detailed solution

Correct option is B

U2 = 12kl22   U1 = 12kl12W = U2-U1    = 12kl22-12kl12 = 12k(l22-l12)

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Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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