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The work done by a force F=2(x+4y)i^+8xj^N on a particle moving from origin to (4 m, 2 m, 0) along the path x2 = 8y is 10×n J. The value of n is_______

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Detailed Solution

W=∫F→⋅dr→=∫{2(x+4y)i^+8xj^}⋅(dxi^+dyj^)=∫(2xdx+8ydx+8xdy)=∫04 2xdx+8∫0,04,2 d(xy)=[x2]04+8[xy]0,04,2=16+8×8=80J∴10n=80⇒n=8

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