First slide

Work done by Diff type of forces

Question

The work done by the force = $\vec{F} = A (y^{2} \hat{i} + 2 x^{2} \hat{j})$ , where A is a constant and x and y are in meters around the path shown is:

Moderate

A

zero
B

Ad
C

A $d^{2}$
D

$A d^{3}$

Solution

$\int F . dx = \int A (y^{2} \hat{i} + 2 x^{2} \hat{j}) (dx \hat{i} + dy \hat{j})$
= A $\int (y^{2} dx + 2 x^{2} dy)$
$W_{OA} = 0 + 0, W_{AB} = A [0 + 2 d^{2} d]$
$W_{BC} = A [d^{2} (- d) + 0], W_{CD} = A [0 + 0]$
$W = 0 + 2 {Ad}^{3} - {Ad}^{3} + 0 = {Ad}^{3}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App