First slide
Work
Question

The work done by a force of i^+2j^ is zero, when a particle is moving along the line 4y+kx=3. The value of K is ________

Difficult
Solution

W=FΔr=(i^+2j^)(Δxi^+Δyj^)0=Δx+2ΔyΔyΔx=124y+kx=3y=kx4+34ΔyΔx=k4⇒=12=k4k=2

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