The work done by a force of (2xi^+30j^)N in displacing the particle from (1,0,2) m to (2,y,2) m is zero. The value of y is
1
-1
3
-3
W=∫Fxdx+∫Fydy0=∫12 2xdx+∫0y 3dy0=2x2212+3(y−0)0=3+3y⇒y=−1