First slide
Work
Question

The work done by a force of (2xi^+30j^)N in displacing the particle from (1,0,2) m to (2,y,2) m is zero. The value of y is

Moderate
Solution

W=Fxdx+Fydy0=122xdx+0y3dy0=2x2212+3(y0)0=3+3yy=1

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