Questions
The work done in carrying a charge of 5 C from point A to a point B in an electric field is 10mJ. The potential difference VB- VA is then
detailed solution
Correct option is B
wAB=5μCVA−VB⇒10mJ5μC=VA−VB ∴ VA−VB=2kV or VB−VA=−2kVTalk to our academic expert!
Similar Questions
A positive charge q and a negative charge -q are placed at x = -0 and x = + a respectively. The variation of V along X - axis is represented by the graph.
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