Work done in converting 1 g of ice at -10oC into steam at 100oC is

Work done in converting 1g of ice at −10∘C to steam at  100∘C= Heat sunplied to raise temperature of 1g of ice from −10∘C  to 0∘Cm×cice ×ΔT + Heat supplied to convert 1g ice into water at 0∘Cm×Lice + Heat supplied to raise temperature of 1g of water from 0∘C to 100∘Cm×cwater ×ΔT + Heat supplied to convert 1g water into steam at 100∘Cm×Lvapour =m×cice ×ΔT+m×Lice +m×cwater ×ΔT+m×Lvapour =[1×0.5×10]+[1×80]+[1×1×100]+[1×540]=725cal=725×4.2=3045J