First slide

Work done by Diff type of forces

Question

The work done in dragging a stone of mass 100 kg up an inclined plane 1 in 100 through a distance of 10 m is (take g = 9.8 $m / s^{2}$ )

Easy

A

zero
B

980 J
C

9800 J
D

98 J

Solution

Slope of inclined plane, sin $θ$ = $\frac{1}{100}$
Component of weight down the inclined plane
F = mg sin $θ$ = $100 \times 9.8 \times \frac{1}{100} = 9.8 N$
s =distance moved = 10 m
W = Fs = 9.8 $\times$ 10 = 98 J

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