First slide

Surface tension

Question

The work done in increasing the size of a soap film from 10 cm $\times$ 6 cm to 10 cm $\times$ 11 cm is $3 \times 10^{- 4}$ Joule. The surface tension of the film is

Moderate

A

1.5 $\times$ $10^{- 2} N / m$
B

$3.0 \times 10^{- 2} N / m$
C

$6.0 \times 10^{- 2} N / m$
D

$11.0 \times 10^{- 2} N / m$

Solution

W = $T \times ∆ A T = \frac{W}{∆ A}$
T = $\frac{3 \times 10^{- 4}}{2 \times (110 - 60) \times 10^{- 4}}$
= 3 $\times 10^{- 2} N / m$

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