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Q.

The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10-4 joule. The surface tension of the film is

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a

1.5×10−2N/m

b

3.0×10−2N/m

c

6.0×10−2N/m

d

11.0×10−2N/m

answer is B.

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Detailed Solution

W=T×ΔA ∴T=WΔAT=3×10−42×(110−60)×10−4 (Soap film has two surfaces) =3×10−2N/m
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The work done in increasing the size of a soap film from 10 cm× 6 cm to 10 cm × 11 cm is 3 ×10-4 joule. The surface tension of the film is