First slide

Work done by Diff type of forces

Question

The work done in lifting a body of mass 20kg and specific gravity 3.2 to a height of 8m in water is, (g = 10 m/ $s^{2}$ )

Moderate

A

110 J
B

1600 J
C

500 J
D

1100 J

Solution

B = Buoyant force = ρ.vg = ρ . m/ $σ$ . g
W = mg
.: $W_{a}$ = Apparent weight = mg - mg . ρ/σ
.: Work done = $W_{a}$ .S = mg S (1 - ρ/σ)
= 20 x 10 x 8( $1 - \frac{1}{3.2}$ )
= 1100 J

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