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The work done in moving a body of mass 4 kg with uniform velocity of 5 $m s^{- 1}$ for 10 seconds on a surface of $μ$ = 0.4 is (take g = 9.8 $m / s^{2}$ )

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Correct option is B

Force to be applied (against friction), F = μmg = 0.4×4×9.8 = 15.68 NDisplacement, s = vt = 5 × 10 = 50 m/s Work = Fs = 15.68 ×50 = 784 J

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The work done in moving a body of mass 4 kg with uniform velocity of 5 ms-1 for 10 seconds on a surface of μ = 0.4 is (take g = 9.8 m/s2 )

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The work done in moving a body of mass 4 kg with uniform velocity of 5 $m s^{- 1}$ for 10 seconds on a surface of $μ$ = 0.4 is (take g = 9.8 $m / s^{2}$ )