First slide

Thermodynamic processes

Question

Work done per mol in an isothermal change is

Moderate

A

${RTlog}_{10} \frac{V_{2}}{V_{1}}$
B

${RTlog}_{10} \frac{V_{1}}{V_{2}}$
C

${RTlog}_{e} \frac{V_{2}}{V_{1}}$
D

${RTlog}_{e} \frac{V_{1}}{V_{2}}$

Solution

For isothermal process $PV = RT \Rightarrow P = \frac{RT}{V}$
$∴ W = PdV = \int_{V_{1}}^{V_{2}} \frac{RT}{V} dV = {RTlog}_{e} \frac{V_{2}}{V_{1}}$

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