Questions
The work done required to put the four charges together at the corners of a square as shown in fig. is
a
14πε0×q2a
b
−2⋅64πε0×q2a
c
2⋅64πε0×q2a
d
none of these
detailed solution
Correct option is B
See fig. The work done required is equal to the potential energy of the system. Thus W=U=14πε0q1q2r12+q2q3r23+q3q4r34+q4q1r41+q1q3r13+q2q4r24=14πε0−q2a−q2a−q22−q22+q2a2+q2a2 =14πε0−4q2a+2q2a2=q2−4πε0a[4−2]=−2⋅64πε0×q2aTalk to our academic expert!
Similar Questions
Three point charges of equal value q are placed at the vertices of al equilateral triangle. The resulting lines of force should be sketch as in
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
