The work done in rotating a magnet of magnetic moment 2 Am2 in a magnetic field of 5 x 10-3 T from the direction along the magnetic field to opposite direction to the magnetic field, is
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a
Zero
b
2 x 10-2 J
c
10-2 J
d
10 J
answer is B.
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Detailed Solution
W = MB(1- cosθ), where θ = 180o⇒W = 2MB⇒ W = 2 x 2 x 5 x 10-3= 2 x 10-2 J