First slide

Surface tension and surface energy

Question

Work done in splitting a drop of water of 1 mm radius into 10⁶ droplets is (Surface tension of water $= 72 \times 10^{- 3} J / m^{2})$

Moderate

A

$9 .58 \times 10^{- 5} J$
B

$8 .95 \times 10^{- 5} J$
C

$5 .89 \times 10^{- 5} J$
D

$5.98 \times 10^{- 6} J$

Solution

Work done in splitting a water drop of radius R into n drops of equal size $= 4 {πR}^{2} T (n^{1 / 3} - 1)$
$\begin{array}{l} = 4 π \times {(10^{- 3})}^{2} \times 72 \times 10^{- 3} \times (10^{6 / 3} - 1) \\ = 4 π \times 10^{- 6} \times 72 \times 10^{- 3} \times 99 = 8 .95 \times 10^{- 5} J \end{array}$

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