First slide

Work

Question

The work done in stretching a spring through 2cm is 10J. The work done in stretching the spring further through 6cm is

Moderate

A

160J
B

320J
C

90J
D

360J

Solution

$\begin{array}{l} \frac{W_{2}}{W_{1}} = \frac{\frac{1}{2} k (x + y)^{2}}{\frac{1}{2} k x^{2}} \\ W_{2} = 10 \times {(\frac{2 + 6}{2})}^{2} = 10 \times 16 \\ W_{2} = 160 J \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App