The work done in turning a magnet of magnetic moment M by angle of 90o from the meridian, is n times the corresponding work done to turn in through an angle of 60o. The value of n is given by
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a
2
b
1
c
1/2
d
1/4
answer is A.
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Detailed Solution
W1=MBcos0∘−cos90∘=MB(1−0)=MBW2=MBcos0∘−cos60∘=MB(1−1/2)=MB/2∴W1=2W2 or n=2
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The work done in turning a magnet of magnetic moment M by angle of 90o from the meridian, is n times the corresponding work done to turn in through an angle of 60o. The value of n is given by