The work function of a metallic surface is 5.01 eV. The photo-electrons are emitted when light of wavelength 2000 Å falls on it. The potential difference applied to stop the fastest photoelectrons is:
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a
1.2 volts
b
2. 24 volts
c
3.6 volts
d
4.8 volts
answer is A.
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Detailed Solution
Energy of incident lightE=123752000=6.18eVAccording to relation E=W0+eV0⇒V0=E−W0e=(6.18eV−5.01eV)e=1.17V≈1.2V