First slide
Photoelectric effect and study of photoelectric effect
Question

The work function of a metallic surface is 5.01 eV.  The photoelectrons are emitted when light of wavelength 2000  falls on it. The potential difference applied to stop
the fastest photoelectrons is h=4.14×1015eVs

Easy
Solution

eV=hvϕ0=1237520005.01eVV=(6.18755.01)V=1.18V1.2V

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